Can you set the “code set style” of a corridor with dynamo?
If I use the “documentExtensions.setstyle”, it sets the style but not the “code set style”.
Hi,
I didn’t find a node for that either, but you can do it with python script.
# Load the Python Standard and DesignScript Libraries
import sys
import clr
# Add Assemblies for AutoCAD and Civil3D
clr.AddReference('AcMgd')
clr.AddReference('AcCoreMgd')
clr.AddReference('AcDbMgd')
clr.AddReference('AecBaseMgd')
clr.AddReference('AecPropDataMgd')
clr.AddReference('AeccDbMgd')
# Import references from AutoCAD
from Autodesk.AutoCAD.Runtime import *
from Autodesk.AutoCAD.ApplicationServices import *
from Autodesk.AutoCAD.EditorInput import *
from Autodesk.AutoCAD.DatabaseServices import *
from Autodesk.AutoCAD.Geometry import *
# Import references from Civil3D
from Autodesk.Civil.ApplicationServices import *
from Autodesk.Civil.DatabaseServices import *
# The inputs to this node will be stored as a list in the IN variables.
dataEnteringNode = IN
corridorin = IN[0]
stylename = IN[1]
def codesetstyle(corridorin,stylename):
adoc = Application.DocumentManager.MdiActiveDocument
editor = adoc.Editor
with adoc.LockDocument():
with adoc.Database as db:
with db.TransactionManager.StartTransaction() as t:
#Get corridor ID
corridorId = corridorin.InternalObjectId
# Open corridor object
corridor = t.GetObject(corridorId, OpenMode.ForWrite)
#Set code set stlye
corridor.CodeSetStyleName = stylename
# Commit before end transaction
t.Commit()
# Assign your output to the OUT variable.
OUT = codesetstyle(corridorin,stylename)
corridorcodesetstyle.DYN (6.1 KB)
2 Likes
Hello,
Both solutions work perfectly!
Thanks Kovacsv and Shahid.