Room corner coordinates

[bjkris]

hi there All

I am still very new to this, so I’m still trying as I go…

So what I need to get from my model, is all rooms corner coordinates, on the level they belong to.

So the way I have tried approaching it, is by following this thread, but no luck (probably because i’m not sure, what im doing )

How to get the coodinatess of the rooms in Revit with Dynamo

You could try Element.Geometry on the rooms, get bottom surface , explode into lines,Curve.StartPoint on all of them and you get corner coordinates, for the center one, Surface.PointAtParameters 0,5;0,5 .

So what I am trying to do, is:

• Find all rooms geometry
• Find the bottom of the room, by finding where it intersects with the level.
• Divide this to lines
• Find the startpoint.

HELP!

[lucamanzoni]

Something like this?

[bjkris]

oooh yes, is it that simple…?

What are the coordinates in relation to here? is that from origin in the model or is it from base point or?

[m.rijsmus]

it relates to revit 0,0,0 point (the same as Survey and Project base point in a new file with the “None” template)

[bjkris]

I found, that in my model it is according to the “project base point”. Problem is, that i need the coordinates to be in relations to the “survey point” is there a way to change that in your graph`?

[Alban_de_Chasteigner]

Hi Bjarke,

Add the node Convert Point in Coordinate Systems of the Genius Loci package after the node Curve.StartPoint.

[lucamanzoni]

Nice node @Alban_de_Chasteigner. I was just trying this way, it should work as well:

[bjkris]

Thanks for the graph Alban! But is it only available for Dynamo 2.0? Because for the time beeing, we only use Revit 2016, and older versions of Dynamo…

And I am going to try yours as well LucaManzoni!

[Alban_de_Chasteigner]

Hi,

The node is also available in Dynamo 1.3. (I didn’t test it in Dynamo 1.2)