Hello all,
I have a small and perhaps simple question but I can’t figure it out.
I have a list of doubles whose index I want to fetch.
But the List.IndexOf node returns only -1.
Anyone any idea?
@Nick_Boyts maybe?
Thanks for contributing ideas.
Looks like you have two minor issues.
- Your list levels are off. You want to check the list, which is
@L2, for the item. - Your object types don’t match. An
intwon’t match with adoubleeven if they’re the same value. Use10.0instead.
Also, useAllIndicesOfif you want every instance of the item, not just the first.
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Thanx a lot Nick!
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Yet another question…
I want to replace the items in the list in the watch node with the values from the code block based on the indexes from the List.AllIndicesOf node.
So index 0 should become k, index 1 and 3 should become k+v and index 2 then k-v.
You’ll need a custom node (Clockwork has one and I think Orchid as well) to replace multiple items at once.
Hello @Fernand77 …is it something here you need…
are you sure your indicies are integers???
Pull apart the custom node and make sure everything is working as expected. You may be missing IronPython2. I would also recommend simplifying your list structure if possible.
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yeah i would do as Nick say simplify your list…or try to play around with your list levels in your custom node try @L3 in indicies…i see you are in a old clockwork version,not sure probably difference in versions,try to install the latest clockwork version and oh yeah Iron python 2 
You request 4 replacements with 3 values
(you have to add a “k+v” before the “k-v”)
if you make a long combination you will have a “k-v” otherwise
[“k”,“k+v”,“k+v”,“k-v”]
cordially
christian.stan
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no that won’t work.
all items in list 0 must be replaced by k, all items in list 1 by k+v and all items in list 2 by k-v.
yes i understand but that is not what i want.
The List.AllindicesOf will always be 3 lists on @L2, but @L1 is different every time.
Actually as I indicate in the picture with the arrows.
or is it possible to create a list based on another list?
Like in the picture below?
Hi @Fernand77 i am not 100 sure what you mean…probably something
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