You want without adding a “k+v”
I’m thinking
cordially christian.stan
no, the list is not static.
So at @L2 there are always 3 lists but the items in these 3 lists are dynamic and different each time. Sometimes a list has only 1 item, but it can also be 10.
Do you understand what I mean?
list A is a variable list. now there are 4 items but this can also be 10 or more.
List A determines the number of items (also 4)
in list B.
And the number of lists in list B is always 3.
These items are randomly distributed over the 3 lists.
And so what I want is that all items in list 0 (of list B) are always replaced by k, in list 1 all items are always replaced by k+v, and all items in list 2 are always replaced by k-v.