Hi Forum
I have searched the forum and looked at every topic on this subject but I cannot find an example to solve my issue, which I think should be simple.
I would like to replace the 00 in the list with GROUND from another list with the same index value. I have used the AllIndicidesof node to get the index 2, but I cannot seem to find the best node to replace the value. All of the nodes for List.replaceItemAtIndex (also the Clockwork one) do not give the result I need.
The result in this case should be
-
- GROUND
-
Any thoughts would be greatly appreciated.
Many thanks
Tim
Apologies, my example list should be:
-
- GROUND
-
Thanks!
Hi Forum
I seem to do this, as soon as I post an idea comes to me. Here is the solution I have worked up…
Seems to work well.
Many thanks
Tim
Hi Tim,
See a more simple solution below:
Hope it helps,
Jake
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Hi Jake
Many thanks for looking at this. This is not quite what I need, it is the 3 index list I am looking to update, not the full list of levels. But the technique is great, I will see if I can use the IF statement approach.
Many thanks
Tim
Hi Tim,
Apologies I missed that!
In which case I would go down the dictionary route as below:
Not sure why your initial list has 3 entities but 2 are empty? Might be worth cleaning that data before doing a check with it. I did the inverse and just extracted the element from the list to feed into the Dictionary.ValueAtKey (the non erroring node).
Hope this solves your issue!
Thanks again Jake!
I really need to get more familiar with the Dictionary approach. Thank you. Part of this challenge for me is to maintain the list structure with the blank data as this is key for the following stages in the graph. Essentially it is concating a long string together, and it could be blank or filled out, but the list structure needs to remain.
Thanks again, I will give Dictionaries a go. Cheers
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No problem at all Tim,
Best place to go to learn this stuff is always the primer:
https://primer.dynamobim.org/09_Dictionaries/9_Dictionaries-In-Dynamo.html
Secondly - If you wish to keep the list structure with the empty strings that is no issue. Just include a like for like empty string (“”) Key/Value pair in the dictionary values like below. This makes the initial node in my screengrab not error
[“B2”,“B1”,“00”,“01”,“02”,“”];
[“Base1”,“Base2”,“Ground”,“First”,“Second”,“”];
All the best,
Jake
1 Like
Hi Jake
This is a very nice way to solve the issue, thank you very much indeed for your help.
Much appreciated!
Best
Tim
1 Like
