Hello
Im trying to get a list that have the same structure as the parent list with all unique entries.
To clarify more, the below picture has a parent list (26 entries) consisting of 4 sub-lists:
the third sub-list has the last entry as “15” and is duplicated in the 4th sub-list. what I’m trying to accomplish is this (keep drop the nth entry whenever it is duplicated):
25 entries by dropping the duplicate in the 4th list.
I’ve tried using indexing like this:
but i couldn’t get anywhere.
any help is much appreciated.
Hi @NERDASORUS
Here this might be of help:
list_of_lists = IN[0]
# Step 1: Flatten the list of lists
flattened_list = [item for sublist in list_of_lists for item in sublist]
# Step 2: Use a set to identify unique elements
unique_elements = set(flattened_list)
# Step 3: Create a new list of lists with unique elements only
unique_list_of_lists = []
seen_elements = set()
for sublist in list_of_lists:
unique_sublist = []
for item in sublist:
if item in unique_elements and item not in seen_elements:
unique_sublist.append(item)
seen_elements.add(item)
if unique_sublist:
unique_list_of_lists.append(unique_sublist)
# Output the result
OUT = unique_list_of_lists
Just open a python node and paste this code as it is, it’ll help you get exactly what you trying to do.
regards,
BM
Instead of checking if the last item is repeated, you could just ensure no member of a sub-list repeats in a subsequent one
unique.dyn (13.9 KB)
