Create a subList of repeated item, but only one time in a list - PYTHON

[EricRevit]

Hello DynamoUser,

I’d like some help solving my problem… I am not a Python User but I’m doing my best to learn.
Here is the issue : I would like to obtain a List of lists from a initial list, that contains only the element that are repeated more than once, but only one time.

EXEMPLE IMAGE :
0 appears only one time, so I don’t want it in the final list

1 & 2 appears twice, so I want them in the sublist of the final list

3 appears twice so I want him in the sublist containing 3 and 4
4 appears 3 times
5 same as 3

So as I said, not a Python User
But here is the beginning of my reflexion
(only read the dynamo primer course so…)

import clr
import sys
sys.path.append('C:\Program Files (x86)\IronPython 2.7\Lib')
import System
from System import Array
from System.Collections.Generic import *
clr.AddReference('ProtoGeometry')
from Autodesk.DesignScript.Geometry import *
clr.AddReference("RevitNodes")
import Revit
clr.ImportExtensions(Revit.Elements)
clr.ImportExtensions(Revit.GeometryConversion)
clr.AddReference("RevitServices")
import RevitServices
from RevitServices.Persistence import DocumentManager 
from RevitServices.Transactions import TransactionManager 

clr.AddReference("RevitAPI")
clr.AddReference("RevitAPIUI")

import Autodesk 
from Autodesk.Revit.DB import *
from Autodesk.Revit.UI import *




#List that contain multiple list of the number we want to assemble
IN[0]=List_Of_IndexToAssemble

#List that contain multiple list with the numbers that appears more thant once, but only one time
result=[]

#GOAL : ADD THE NUMBER_a only one time in a list IF IT APPEARS MORE THAN ONCE with the NUMBER_b + AND + Also take count the NUMBER_c in the list with the other number i NUMBER_c is with NUMBER_b

#Check in all list, it the number appears more than ONCE

for counter in List_Of_IndexToAssemble
	if counter.List.Count > 1
	result.append(counter)
	#If it appears more than once, put it in a _sublist_ with the others that appears with it

#Create a List with all _sublist_ 



OUT = result

Thanks all for your prescious time

Eric

[c.poupin]

Hello
a solution using set operator

def checkuniq(lstobj):
	#flatten
	flatt = sum(lstobj, [])
	outList = []
	for sublstx in lstobj:
		if not all([flatt.count(item) == 1 for item in sublstx]):
			common = []
			for sublsty in lstobj:	
				#search commons sublist 		
				inters = set(sublstx) & set(sublsty)
				if inters:
					common.extend([sublstx, sublsty])
			#get the largest common sublist			
			finalcom = sorted(common, key=len)[-1]	
			if finalcom not in outList:
				outList.append(finalcom)					
	
	return [list(x) for x in outList]

varlst = IN[0]

OUT = checkuniq(varlst)

Note
not work if elements of a sublist is communs with others differents sublist

[EricRevit]

Thanks you !!

amazing you made my day friend.

Eric