Hello, How can I round down or up my values to specific numbers in code block? Below screenshot with some random values: Regards [obraz]

Think I might have misunderstood at one point, but this is certainly much easier than infinitely nesting if statements and removes the need for both imperative code and python. [Down up_2023-09-04_03-10-25]

Think you want this: Find closest value from list B into list A - #3 by Vikram_Subbaiah

Hello, Here is this track dig [Forum english 02 septembre 2023_2023-09-02_03-36-34] cordially christian.stan

Unfortunately no. Columns “Down” and “Up” should be in separate lists. List “value” compare numbers from code block and generate two lists. List A values rounded down and list B values rounded up.

@AeM_86 , i don`t if this is to straight forward … :wink: [image] KR Andreas

@Draxl_Andreas That’s not the point. For Your values list “Down” and “Up” should be: [obraz] Answers for list B and C are from list D.

if you’re up for some python, you could modify the approach mentioned in this SO post. for example: import bisect def round_down(x): intvals = [5000, 7500, 10000, 20000, 30000, 40000, 50000] i = bisect.bisect_right(intvals,x) return intvals[i-1] where “intervals” are your given list …

The first link can be modified to suit your situation. Get the absolute distance from the sample to the up and down value. Find the index of the smallest distance value. Take the up/down value at that index. As you only have a Up and Down value you could also use an if statement. In design script…

Maybe less professional but worked for me something like this for now. But I’ll test this solution. [obraz]

hello, the es2 function is what you are looking for, I left the essai function just in case [Forum english 03 septembre 2023_2023-09-03_01-51-28] def essai(numb:var[],lst:var[]) { c=[]; loop=[Imperative] { for (i in (0..(DSCore.List.Count(numb)-1))) { if (numb[i] == lst[0]) { c[i]=[lst[0],…

Hi, I see there is a lot of solutions but just wanted to see if this approach could help . If we simply put the ranges in and than determine what range does a number belong to it should solve it all. [image] inputs_1 = IN[0] set_ranges =IN[1] round_down = IN[2] diff = [] for inp in inputs_1: …

Round up or down to specific number?

DesignScript

christian.stan September 2, 2023, 1:39pm 3

Hello,
Here is this track dig

cordially
christian.stan

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Round up or down to specific number?

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