Hi, yes of course i tried this but, as you can see on the screenshot on top, i try to attribute 1 item of the list with the 1 item of the second list.
My objective is to create a list of point(by two) as x = 26; y = a; z = b and x = 474; y = a; z = b
I have tried many mix with list.join and list.create ans list.transpose but don’t arrived at my end.
Maybe if the results of curve.pointasequalchordlength are a simple list i can do something.
Thank you very much for your help !
@Fiesta
I know who to create the crosstie x time (x is the number of frame i need (it’s a var, it depends of the need) )
I have tried many mix but nothing work
The picture below is the part of dynamo who create the crosstie :
Comments are on the dynamo
Fiesta
February 12, 2019, 11:08am
24
sorry…i have not enough time jet…i will help you later:
No problem, thanks for your time today.
I do your solution on my dynamo and there is the results :
I have thinking number in k[ … ] was the number of the list but no in fact
This solution only work for the first patern of mount.
Thank you again.
MDR
It works, i search for a short solution but it works.
Many thank’s for your help !
It was a very short but very effective work !
1 Like
@Fiesta
Hi, I found a solution for my problem.
Remind the initial problem :
As you can see, on the screenshot, my point exit are in this form :
list
If you use list.transpose in this case you don’t obtain the points you need to place your adaptive component with two point.
To place your adaptive component by two point you need that type of form :
__list 0
To delete a “level” of list you need flaten node in exit of point.bycoordonate to get this :
list
Now if you transpose this type of list you obtain that :
__list 0
This is the dynamo of the solution :
Fact :
Flaten remoove you a level of list in a list. It can also delete null value of a list.
list.transpose work like this (bold is enter, green is the exit)
I hope this final post will be helpfull for us !
See you soon on forum.dynamobim.com
Fiesta
February 14, 2019, 10:56am
28
Im happy that you found a solution, or understand how to use the nodes:)
