I want point.pruneduplicates on a big tolerance. 5000mm but it is not working.

i am placing random points on a surface, but i want tohe points to have a minimum distance from eachother.

I am a beginner in Python, trying to find the time to learn more (especially after last years BILTeur)

i only need the random points in a flat surface, i found some code, but how to get this into a dynamo node.

```
import numpy as np
import matplotlib.pyplot as plt
def generate_points_with_min_distance(n, shape, min_dist):
# compute grid shape based on number of points
width_ratio = shape[1] / shape[0]
num_y = np.int32(np.sqrt(n / width_ratio)) + 1
num_x = np.int32(n / num_y) + 1
# create regularly spaced neurons
x = np.linspace(0., shape[1]-1, num_x, dtype=np.float32)
y = np.linspace(0., shape[0]-1, num_y, dtype=np.float32)
coords = np.stack(np.meshgrid(x, y), -1).reshape(-1,2)
# compute spacing
init_dist = np.min((x[1]-x[0], y[1]-y[0]))
# perturb points
max_movement = (init_dist - min_dist)/2
noise = np.random.uniform(low=-max_movement,
high=max_movement,
size=(len(coords), 2))
coords += noise
return coords
coords = generate_points_with_min_distance(n=8, shape=(2448,2448), min_dist=256)
# plot
plt.figure(figsize=(10,10))
plt.scatter(coords[:,0], coords[:,1], s=3)
plt.show()
```

or this code?

```
import numpy as np
import matplotlib.pyplot as plt
# specify params
n = 500
shape = np.array([64, 64])
sensitivity = 0.8 # 0 means no movement, 1 means max distance is init_dist
# compute grid shape based on number of points
width_ratio = shape[1] / shape[0]
num_y = np.int32(np.sqrt(n / width_ratio)) + 1
num_x = np.int32(n / num_y) + 1
# create regularly spaced neurons
x = np.linspace(0., shape[1]-1, num_x, dtype=np.float32)
y = np.linspace(0., shape[0]-1, num_y, dtype=np.float32)
coords = np.stack(np.meshgrid(x, y), -1).reshape(-1,2)
# compute spacing
init_dist = np.min((x[1]-x[0], y[1]-y[0]))
min_dist = init_dist * (1 - sensitivity)
assert init_dist >= min_dist
print(min_dist)
# perturb points
max_movement = (init_dist - min_dist)/2
noise = np.random.uniform(
low=-max_movement,
high=max_movement,
size=(len(coords), 2))
coords += noise
# plot
plt.figure(figsize=(10*width_ratio,10))
plt.scatter(coords[:,0], coords[:,1], s=3)
plt.show()
```

please help

These are more than one questions.

- pruneDuplicates:

I think your tolerance is so high that no points can be delete.

You can put a python code in a python node

3. Dynamo uses ironpython 2.7

You canâ€™t use numpy

i think that Dynamo uses your Revit Project settings for units.

5000 == 5000 meters, use 0.5 / 0.05 instead.

I know we can place it in a nodeâ€¦ but what do i change to set as input IN and output OUT

need to adjust the code for that.

Your first line of python wonâ€™t work in Dynamo as it uses iron python which is capped at 2.7 so numpy wonâ€™t import.

Can you post a sample file so someone can try and reproduce the issue youâ€™re having with the prune duplicates node?

Are you in Dynamo Sandbox, Dynamo Revit, Dynamo for Civil 3D, Dynamo for Formit, Dynamo for Alias, orâ€¦ also if in anything but sandbox what are your project units in that file?

what i am trying nowâ€¦ based on the max X and Max Y and the minimum distance you have an maximum amount of pointsâ€¦ if i random the points on the X axis and i do that times the maximum lines Yâ€¦ then i should get the random points i needâ€¦I think

test.dyn (56.6 KB)

I wrote a script once to place random trees inside a polygon:

Script added, I hope you can understand how I did:

bonus 02 - Random bomen - resultaat.dyn (33.8 KB)

Basically it creates an cross-product of the divided X and Y and corrects it with a random value. To be sure they donâ€™t touch eachother, there is an extra correction distance.

i think it is working, but it is running for everâ€¦is that correct (already running 10min) @Anton_Huizinga

I think you have a huge area and a short distance between the points.

Dynamo is not fast, maybe you can optimize the script. But I advice to try it first on a small area

Or leave out the inside polygon node, since you position the points on a Surface anyway.

could i get some help with this:

i have this codeâ€¦ but i want it to accept multiple inputs (see math.ceiling)

But i also want it to output the list x timesâ€¦ so get an extra input repeat (this repeat will be a list as well)

So you get.

list 0 (this is the math.ceiling list)

------list 0 (number of times repeat)

-------------0 value

-------------1 value

-------list 1 (number of times repeat)

-------------0 value

-------------1 value

-------------2 value

list 1 (this is the math.ceiling list)

------list 0 (number of times repeat)

-------------0 value

-------------1 value

-------list 1 (number of times repeat)

-------------0 value

-------------1 value

-------------2 value

```
import random
NumberOfPoints = IN[0]
MinimumDistance =IN[1]
MaximumDistance = IN[2]
d = sorted(random.randint(0, MaximumDistance-1) for _ in range(NumberOfPoints))
o = [b - a for a, b in zip([0] + d[:-1], d)]
outputlist=([i * MinimumDistance + sum(o[:i + 1]) for i in range(NumberOfPoints)])
OUT = outputlist
```