My Python list will take IN[2] value, but not when I assign the string value directly in the code. Are string values not all equivalent?

Revit
,
1

My current script will receive a list of strings and when a string value is equal to IN[2] (or IN[3]) then the value will be replaced with "NULL". And yet if I define a variable with the desired value ( Weld1 = "307623") with the same value that I define in a code block. It does not work. And no error message either. I am completely stumped on this one. It was my understanding that if I define Weld1 = IN[1], which IN[1] is wired to a code block with the contents of "307623", then that would be the same as if I define

Weld1 = "307623"

Here is my code below. The IN[0] is a list of strings that all portray the Type Id value of items in revit.

import clr
clr.AddReference('RevitAPI')
clr.AddReference("ProtoGeometry")
clr.AddReference("RevitNodes")
clr.AddReference("RevitServices")
clr.AddReference('RevitAPIUI')
import Autodesk
import Revit
clr.ImportExtensions(Revit.GeometryConversion)
import RevitServices
from Autodesk.Revit.DB import *
from Autodesk.DesignScript.Geometry import *
from RevitServices.Persistence import *
from RevitServices.Transactions import *
clr.AddReference('DSCoreNodes') 
import DSCore as DS
from DSCore import *

#import sys	#clr.ImportExtensions(Revit.Elements)	#from Revit.Elements import *	#clr.ImportExtensions(Revit.GeometryConversion)	#from Revit.GeometryConversion import *	#clr.ImportExtensions(Revit.GeometryReferences)	#from Revit.GeometryReferences import *	#import System	#from System.Collections.Generic import *	#from System import *

####### Trying to remove the specified values from IN[0] list
######Step 1: Get all indices of values present in current list
#####Step 2: Remove Items at said Indices

lost=IN[0]					#List of parameter values to
#list = lost
#ShortList=IN[1]	#list of string values
str1=("307623")	#value to remove from list
#Weld1 = str1
str2=("308609")	#value to remove from list
#Weld2 = str2
				#strs = str1.Append(str2)
cnt=len(lost)
inx=0
num1 = []
num2 = []
indices=[]
Output = 0
x = 0

#Weld1 = IN[2]
Weld2 = IN[3]
Weld1 = "Type Id : 307623";
#Weld2 = "308609"
rep = IN[1]
elementlist = list()
for item in lost:
	if item is Weld1:
		item = rep
	elif item is Weld2:
		item = rep
	elementlist.append(item)




#str3i = str1i + str2i
#output = List.RemoveItemAtIndex(list, indices);
#NewID = [A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z];
#if NewID==(0):
#	List.RemoveItem
#List.RemoveIfNot(NewID, (>=0));

OUT = elementlist

I apologize for all the comments in my code.

2

Hey,

Apologies I’m trying to get my head round your issue… TBH I think that if you made a very simple python just to test this, you’d work it out… It would definitely help my tiny brain :smiley:

Cheers,

Mark

1 Like
3

@t.large can you post your dyn as well?

I’m not sure if I follow but have a look at the following;

image
image.png1207×559 59.1 KB

2 Likes
4

@t.large also check this article on using the operator “is”

3 Likes
5

@Mark.Ackerley so essentially what have run into is such:
A Python script uses the Variable Weld1
When I define Weld1 = IN[2] then everything goes as planned. And IN[2] is wired to/from a code block with the contents of "307623";
But if I define 'Weld1 = “307623”` it does nothing at all.

@salvatoredragotta Selection Filter.dyn (22.8 KB)
Here is my DYN.
And after a quick read through of that link, I think my problem was just that. I was using is instead of ==

Looks like that was it! Thank you so much @salvatoredragotta ! That was a real headscratcher for me, one I’ll definitely remember!

2 Likes