Editing a list of strings with python

[Harald]

I’m trying to edit a list of strings with a python script. It works in python but not in dynamo.

Code:

# Load the Python Standard and DesignScript Libraries
import sys
import clr
clr.AddReference('ProtoGeometry')
from Autodesk.DesignScript.Geometry import *

# The inputs to this node will be stored as a list in the IN variables.
dataEnteringNode = IN

# Place your code below this line

oldlist = IN[0]
newfamilylist=[]

def returnfamily_string(family):
    x = "Family:"
    if x in family:
            string1 = family.split(x, 1)[1]
            return(string1.split(" ", 1)[1])
            
for y in oldlist:
    newfamilylist.append(returnfamily_string(y))

          
# Assign your output to the OUT variable.
OUT = newfamilylist

[Draxl_Andreas]

@Harald ,

i had here a similar topic

How to get clean name from a linked file?

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spliting by “.rvt” answered someone

KR

Andreas

[Harald]

Sorry, I don’t quite understand. How would I need to edit my code?

[Draxl_Andreas]

@Harald ,

like this ?

# Phython-Standard- und DesignScript-Bibliotheken laden
import sys
import clr
clr.AddReference('ProtoGeometry')
from Autodesk.DesignScript.Geometry import *

# Die Eingaben für diesen Block werden in Form einer Liste in den IN-Variablen gespeichert.
elems = IN[0]
lists = []

for i in elems:
	rvtFileName = i.Name.split(":")[0]
	lists.append([i,rvtFileName])

OUT = lists

[christian.stan]

Hello,
It is possible that I am off the mark on your expectations.

oldlist2=[]

for i in IN[0]:
    oldlist2.append(str(i))
newfamilylist=[]

def returnfamily_string(family):
    x = "Family:"
    if x in family:
            string1 = family.split(x, 1)[1]
            return(string1.split(" ", 1)[1])
            
for y in oldlist2:
    newfamilylist.append(returnfamily_string(y))

          
# Assign your output to the OUT variable.
OUT = newfamilylist

Cordially
christian.stan

[Harald]

Yeah this works. I was not aware I had to manipulate the input list first.

Thank you.

[christian.stan]

you can also do it in the loop

for y in oldlist:
        newfamilylist.append(returnfamily_string(str(y)))

Cordially
christian.stan

[Harald]

Thanks.