For and while loop in combination, how?

Developers
1

Hello,

I do some basic code again:

X = 1
Y = 2

print("{:>4}".format(" "), end = " ")

for X in range(1,11):
print ("{:>4}".format(X), end = " ")

print()

for X in range(1,11):
print ("{:>4}".format(X), end = " “)
while Y <= 10:
print (”{:>4}".format(X * Y), end = " ")
Y += 1
print()
Y=1

Here are a other example:

i = 2
while(i < 100):
j = 2
while(j <= (i/j)):
if not(i%j): break
j = j + 1
if (j > i/j) : print i, " is prime"
i = i + 1

print “Good bye!”

It should create a list of numbers… …how is the translation regarding Print and OUT? There are other translations f.e. print and return. I try to find the gramma between python, C#, … designScript

How can i transform this to designscript, here are my trys:
for_while_loop_loop.dyn (3.0 KB)
2019-03-26_11h45_09

I changed the “prints” to “returns”, but dynamo is still confused, because the returns at wrong points…!
I think i have to change more the Syntax.

I am happy about any advice

KR

Andreas

2019-03-26_12h29_41
2019-03-26_12h29_41.png691×235 19.7 KB
loops.dyn (6.6 KB)

2

Hi,
there are some errors in your code.

  1. Don’t use return - create lists and than insert something in these new lists
    For example with “append”
  2. OUT means output, write list after “OUT=” you want to work outside of the script.
    image
    image.png1249×557 36.3 KB
  3. don’t use the variables of the input ( X and Y) in your “for loops”
3

Hi,

I’m not sure exactly what you want to get… But just to try and clarify…

OUT is everything you want to output… so to ‘print’… make a variable equal the value you want to ‘print’, then output that variable… E.G…

if (j &gt; i/j) : print str(i) + ' is prime'

is changed to

if (j &gt; i/j) : k = str(i) + ' is prime'
OUT =  k

The loops themselves are quite complex, so it’s hard to see what they are meant to be? I’d test on a more simple example until you’re comfortable with them…

If you use append, you’ll see the progression of numbers which might make the process more obvious?

Perhaps have a play with this… FYI, the <> will let you format code… and if you use ’ not " then it will copy and paste into here easier…

i = IN[0]

z = []

while(i < 50):
    j = 2
    z.append(j)
    if not(i%j): break
    i = i + 1


OUT =  z

Hope that helps,

Mark

1 Like
4

Thank you: that`s a clear statment - Dont use return, use .append!

Also the fakt “to store results” in a “empty variable” !

5

a = [ ] is a list, a = 0 is a variable :slight_smile:

If you append into a list, you will OUT a sequence…

So a+1 while a<= 5:
If appended into a list OUT = 1,2,3,4,5
If it equals a variable, you will just get the final value, so OUT = 5