Hi I’m a dynamo new user .I got a stupid questions to want to know,thanks:)
Who can help me do the “loop” plz,thanks
Hi I’m a dynamo new user .I got a stupid questions to want to know,thanks:)
Who can help me do the “loop” plz,thanks
try this using python
mylis= IN[0]
nlis=[]
for a in range(0,len(mylis)-1):
nlis.append(mylis[a])
if mylis[a]+1!=mylis[a+1]:
nlis.append("NON")
#Assign your output to the OUT variable.
OUT = nlis
Hi,
as a new user, I suggest you not to start with DS looping, you almost never need them.
Here is a way to do it without looping, and another way with a Python loop, that is way easier to handle:
a = IN[0]
b = IN[1]
output = []
for x in b:
if x in a:
output.append(x)
else:
output.append("NON")
OUT = output
thanks a lot:) I will learn more about Dynamo~
thanks a lot:)