Hello to all,
I’m trying to make a DS but do not know well yet the syntax, so I’m trying things.
This is what I would get
Can you give me some advice and tell me where to find a guide to the Dynamo internal language?
Thanks so much.
Not sure what you’re trying to achieve, but try this (not tested):
hdfh = [ Imperative]
{
x = {0, 2, 0, 5, 8};
a = {};
for (i in GetKeys(x))
{
l = 0;
a[i] = {};
while (l <= x[i])
{
a[i][l] = x[i];
l = l+1;
}
}
}To achieve your intent in the second image you posted, you can try this:
hdfh = [Imperative]
{
x = {0, 0, 0, 2, 3, 4 ,4 ,4, 5, 7 ,7 ,0, 0, 3, 1, 1, 1};
a = { };
subList = 0;
currentIndex = 0;
for (i in GetKeys(x) )
{
a[subList][currentIndex] = x[i];
currentIndex = currentIndex +1;
if (x[i] != x[i+1])
{
subList = subList + 1;
currentIndex = 0;
}
}
return = a;
};
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Thanks Thomas, is perfect and clear!
Something slightly different:
FOR LOOP
[Imperative]
{
x = {0, 0, 0, 2, 3, 4 ,4 ,4, 5, 7 ,7 ,0, 0, 3, 1, 1, 1};
a = {};
l = 0;
m = 0;
for (i in GetKeys(x))
{
if (x[i] == x[i+1])
{
a[l][m] = x[i];
m = m + 1;
}
else
{
a[l][m] = x[i];
l = l + 1;
m = 0;
}
}
return = a;
};
WHILE LOOP
[Imperative]
{
x = {0, 0, 0, 2, 3, 4 ,4 ,4, 5, 7 ,7 ,0, 0, 3, 1, 1, 1};
a = {};
n = 0;
l = 0;
m = 0;
while (n < Count(x))
{
if (x[n] == x[n+1])
{
a[l][m] = x[n];
m = m + 1;
}
else
{
a[l][m] = x[n];
l = l + 1;
m = 0;
}
n = n + 1;
}
return = a;
};
1 Like