I know you can do what I did and then use x[0] or GetItemAtIndex node, but the reason I do not want that is because it takes a much longer time for hat I am trying to do.
Thanx for the respond. What I want to accomplish is only getting the result in the red squares in the above image. Your way does not help me unfortunately because you are using 2 groups.
I want to use 1 List with sublists. eg list above and use this single list to crossproduct the sublists with themselves , not with other sublist.
I would like to get the results of A and B in 1 with nothing more. Do you know if its possible ?
Only you got the exact opposite result of what I needed haha. you combined the two groups but I need the groups to not combine.
And does this method work for 10 + groups. I have a X-amount of sublists. I never know how much exactly and need this to happen with whatever number X is.
Maybe something with your method and a “Count” node ?
You did make me understand your method a bit more. Thanx!
Ah yes I see what you are trying to accomplish. I haven’t a solution because you going to need more nodes if you want to do this for a x-amount of sublists.
You will indeed need to use the count node I think.
Sadly I have no time at the moment to look further in this problem.
Does not for me. Would you mind showing what the nodes are doing like I did ?
If it does work , I’m gonna test it for more groups.
The reason I wanted sublist to cross themselves is because im working with a lot of lists > 20 @ 3 levels :
List > List > List. I need the bottom list to crossproduct itself. I thought maybe I used the lacing of the node wrong and someone had a quick solution.