I am trying to learn Code Block syntax, and currently toying with creating my own List.FilterByBoolMask with a simple statement; “If Input==10?”, Else; Output==null. I would love to filter the output from the alternative value, and just output the In list. Is this possible within the same Code Block?
Hi @Tue_Kappel - You can keep chaining conditions like so - Is this what you are after?
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To expand on what @solamour indicated around pulling values form a dictionary:
To call the Dynamo function and only return the ‘in’ dataset:
List.FilterByBoolMask(list,filter)['in'];
To be clear, the reason you need to call for the value from a dictionary via key (the ['in'] in the above statement) is that any node with multiple outputs in Dynamo is actually returning a dictionary, where the keys are the output names.
Another way to do this via your own function is as follows. You need to leverage imperative code, a floor loop, and an if statement in this, so it isn’t for the faint of heart. However for those same reasons it’s a good learning exercise. Towards that end I’ve included a comment before each line to outline why I wrote it.
//define the function name, and inputs with structure
def FilterList (list: var[], boolMask: bool[])
//start the definition block
{
//start the return statement as an imperative code block
return [Imperative]
//start the imperative code block
{
//define a new list for results
results = [];
//define a for loop to iterate over th indicies of the list
for (i in 0..List.Count(list) )
//start the for loop code block
{
//get the mask at the index
msk = boolMask[i];
//define an if statement for the mask
if (msk)
//start the if statement block
{
//redefine results to include the item from the list
results = List.Join([results, list[i]]);
//close the if statement block
}
//close the for loop
}
//define the output from the imperative block
return results;
//close the imperative block
}
//close the definition
};
The results in action:
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thank you all for great suggestions. I will try them all, and try to understand. -None of them what i was dreaming of, but all the more teaching moments for this simple mind.
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I found the solution i was looking for…..-List.Clean can remove the null values, and throw away indices via the false value. So i’m left with the list of elements testing positive.Succes!
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Nice one 
and another maybe, but not so cool as yours
hahah see now its the same as your alternative forget it really love the first one…
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