Sorting out strings in a list

[superfabi.krause]

Hello everybody,

Is there a way to sort out all strings from the following list based on the double numerical values?
In the end, each “variant” should only exist once.

Thanks in advance!

[sovitek]

Hello …do you mean something like this

[superfabi.krause]

Many Thanks! That’s exactly what I needed!
But how can I set the @Lx in the “List.LastItem” and “List.UniqueItems” block? This possibility does not exist for me …

[sovitek]

can you show an image ?

[superfabi.krause]

[sovitek]

try to expand the little arrow in right side and set to level2…hope it helps

[c.poupin]

Hello
another solution

import sys
import re

listA = IN[0]
if all(re.search(r'(\d+[\,\.]\d+)', x) is not None for x in listA):
	listA.sort(key = lambda x : float(re.search(r'(\d+\.\d+)', x.replace(',','.')).group(1)))
OUT = listA

[superfabi.krause]

Thanks that was the mistake. It works.

[sovitek]

Yes @c.poupin great way too…your old python shark

[superfabi.krause]

Thanks for your solution. This will sort the values in pairs, right? I think it would work because I can now remove every second value.

[c.poupin]

the code sort list string by decimal value
a small change has been made