Sort list by last two digits

[krzysiektoja]

Hi everyone,

I have a question.

How can I sort this list by the last two digits in order from the smallest to the largest?

I want create list: M.1, M.2, M.2, M.3, M.3, M.3, M.3, M.4, M.5…

Maybe in Python it will be easier to create…(but i dont know how)

Thanks in advance

[sovitek]

Hi @krzysiektoja something here could probably work, in that case…

[krzysiektoja]

Hmm, I dont know why i get null in “e” but in “d” it gives me list I wanted. Thanks

[krzysiektoja]

Maybe You know how can I sort this “element.id” list by this sorted list i get.

[manhgt214]

Dynamo solution or Python like this:

afterSplit, OUT = [], []

for i in IN[0]:
    afterSplit.append(float(i.split("M.")[1]))
    afterSplit.sort()
for i in afterSplit:
    OUT.append(("M."+str(i)).split(".0")[0])

[sovitek]

arhh yeah just delete the last line

[Alien]

What’s the point of the list.shuffle?

[krzysiektoja]

Do you know how can I sort the list with element.id by what I get in sorted list of numbers. I mena I need list with this element.id but arranged in the order dedicated by the sorted list above.

“Parameter.Value” is the same list as “Element.Id”

[manhgt214]

after sorted list, You can get List Id like this:

[krzysiektoja]

thanks, it works