Replace value in dictionary

Lists-Logic
1

Hi,

I have a dictionary that where I want to replace values in dictionary.

dynamo-dictionary-replaceValues
dynamo-dictionary-replaceValues1152×648 111 KB

I created this dictionary with default values:

{“workingSchedule”:{“days”:“0,1,2,3,4”,“from”:“7:00”,“to”:“19:00”},“identifier”:{“displayName”:“x”,“roomNumber”:“y”}};

In the multiple dictionaries created by repetition, I want to replace the value of “x” and “y” per dictionary with the corresponding index of displayName and roomNumber.

I can’t figure out a way to do this. Please help.

2

Are you wanting to end up with completely separate dictionaries for separate displayName, roomNumber pairs or do you want one dictionary with sub-dictionaries for each pair and workingSchedule?

Either way, I don’t think you’ll be able to “duplicate” directly, so you’ll have to recreate the dictionary each time. You can certainly do this with the out of the box nodes but python might be easier. With nodes, it might be easier to pull all your data apart (or start from scratch) and match up all the values. Then just build each dictionary with a unique name/id.

3

A function might work

mltDct
mltDct990×1126 62.8 KB 

def mltDct (x,y){
	return {"workingSchedule":{"days":"0,1,2,3,4","from":"7:00","to":"19:00"},
	"identifier":{"displayName":x,"roomNumber":y}};
	};
5 Likes
4

Hello, I tried in python.

image
image1586×674 101 KB

Python script:

import sys

for i,j,k in zip(range(len(IN[0])),IN[1],IN[2]):
    IN[0][i]["identifier"].update({"roomNumber":k,"displayName":j})
 
OUT = IN[0]

Cordially
christian.stan

2 Likes
5

Thank you @Vikram_Subbaiah ! exactly what I wanted to achieve.

3 Likes