Replace Item in a sublist at Index

Lists-Logic
1

Hi,

I found another posts almost like this… but i still fighting whit this!

(in the first image, all subslists are TRUE AND FALSE, except what i mencioned above, but i’ts not always like this, somethimes i have FALSE AND TRUE, but for me i don’t care. my big problem here is that i CAN’T have TRUE and TRUE.)

image
image.png1212×580 161 KB

2

Change your replacement item from just false to {true,false}. Your graph is working, you’re just not supplying the right list.

3

dont… i tried this before… look image below… it created 945 itens kkkk 106 * 9

image
image.png1084×373 42.6 KB

4

Ah ok. So your problem is that ReplaceItemAtIndex doesn’t replace items simultaneously. If you look at the output, it replaces each index separately, giving you 9 lists instead of one.

EDIT: This issue comes up every once in a while but I honestly don’t remember if there’s a good solution for it besides Python. (That’s how I usually get around it.)

5

exactly!

6

image
image.png1002×613 60.1 KB

7

Here’s a quick and easy way to get around it.

dataEnteringNode = IN
list = IN[0]
bools = IN[1]
replace = IN[2]
output = []

for a,b in zip(list,bools):
	if b == True:
		output.append(replace)
	else:
		output.append(a)

OUT = output

image
image.png1039×597 55.1 KB

8

Thank you Nick!

9

So you’re saying you want to get a single item back, but the lists with two true values returns both items. You can use IndexOf to get the index of the first matching item. It’ll give you a null value if there are none in the list but that should be fine.

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image.png763×774 47.3 KB

You could also use FirstItem to get the first item of each sublist when the mask returns multiple items.