Regex to delete the last part of the code

[akire27]

Hi everyone,
I would like to use regular expression language to get a new list with only num_num and delete everything after the second _.
I am not practical with this language. How can I do it?
Thank you all

[Vikram_Subbaiah]

@akire27

get a new list with only num_num and delete everything after the second _.

Until somebody with Regex expertise might provide guidance specific to your request …

truncateString.dyn (12.2 KB)

[3Pinter]

I would do the @Vikram_Subbaiah,

stringval = "14_102_ui(2)_more_under_scores"
delimiter = "_"
output = stringval.split(delimiter, 2)

print output[0] + delimiter + output[1]
#output = 14_102

but if regex is what you want: ^(.*_.*)_.*

[jacob.small]

Well if we’re putting options on the table:

(edited to add yet another option - down to one line of design script)

[Ewan_Opie]

@3Pinter

^(._.)_.*

Using the expression @3Pinter provided, within a python example.

import re

input = IN[0]
result = []

for i in input:
	result.append(re.split("^(.*_.*)_.*",i)[1])

OUT = result

[akire27]

Thank you all!
Your answers are all solutions.