As the title says, is it possible to query a Level by String name? As I want to use an Excel Spreadsheet to Query specific Levels, I cannot use the Level query by Dropdown menu.
Yes it is:
#Copyright© 2015, Konrad K Sobon
@arch_laboratory, http://archi-lab.net
import clr
clr.AddReference(‘ProtoGeometry’)
from Autodesk.DesignScript.Geometry import *
Import DocumentManager and TransactionManager
clr.AddReference(“RevitServices”)
import RevitServices
from RevitServices.Persistence import DocumentManager
from RevitServices.Transactions import TransactionManager
Import RevitAPI
clr.AddReference(“RevitAPI”)
import Autodesk
from Autodesk.Revit.DB import *
doc = DocumentManager.Instance.CurrentDBDocument
#The inputs to this node will be stored as a list in the IN variable.
dataEnteringNode = IN
levelName = IN[0]
level = None
message = “Name doesn’t match any levels in \n the project. Pick a different one”
allLevels = FilteredElementCollector(doc).OfClass(Level).ToElements()
for i in allLevels:
if i.Name == levelName:
level = i
break
else:
continue
if level == None:
OUT = ‘\n’.join(’{:^35}’.format(s) for s in message.split(’\n’))
else:
OUT = level
I think Andreas added a great little node to the clockwork package recently called “All Elements Of Name” which if combined with a map node, saves you a lot of effort:
Also, added it to the archi-lab package for easy access.
Nice! I like that solution better. There are so many nodes in his package. I don’t even know then all. 
Cheers guys, works great!
Hi Konrad/Dimitar
I have installed Clockwork for Dynamo 0.7x but I can’t find that node All elements of Name.
Was it in a previous package?
Thanks
I renamed it. I think it’s called Elements.FilterByName now.