Python sequence in list

Revit
1

Hi all,

I guess this is an easy one, but I don’t know it anymore :stuck_out_tongue:
I need a loop/while that’s start over after 3 values.

In this case I want 8 values:

PV op L1
PV op L2
PV op L3
PV op L1
PV op L2
PV op L3
PV op L1

image
image885×784 44.6 KB 

x = 1

nummers = []
while x < 100:
	nummers.append("PV op L"+ str(x))
	x += 1
	

OUT = nummers
2

here an example with itertools.cycle()

image
image1177×514 56.5 KB

Edit : code fixed

import sys
import itertools

out = []
if IN[0] is not None:
	cycle_x=itertools.cycle([1,2,3])
	for idx, x in enumerate(cycle_x):
		out.append("Toto L{}".format(x))
		# 'make break and avoid infinite loop
		if idx + 1 == IN[0] or idx > 9999:
			break
		
OUT = out
3 Likes
3

Hello, I tried like this,

# Charger les bibliothèques DesignScript et Standard Python
import sys
import clr
clr.AddReference('ProtoGeometry')
from Autodesk.DesignScript.Geometry import *

# Les entrées effectuées dans ce noeud sont stockées sous forme de liste dans les variables IN.
b=IN[0]
result=[]
a=[]

# Placer votre code au-dessous de cette ligne
num=(b[0]/3)*range(1,4)
num.append(1)
for i in num:
	result.append("Pv op L"+str(i))
# Affectez la sortie à la variable OUT.
OUT = result

I still have work to do :grinning:

thank you
Cordially
christian.stan

1 Like
4

hello again, when I copy / paste your code then save revit freeze, it comes from the python version which does not support itertools (I am under revit 2020)

Cordially
christian.stan

5

Well seen, I guess the IN[0] was null
I fixed my code in previous post

1 Like
6

@c.poupin @christian.stan thank you both!
It was harder than I thought haha

2 Likes
7

I had not yet connected in fact, a beautiful nozzle :smile: I am thank you

cordially
christian.stan

1 Like
8

Good evening, a designscript version (there is surely more efficient)

04 Novembre forum anglais_4_2022-11-04_09-24-16
04 Novembre forum anglais_4_2022-11-04_09-24-16866×450 22.6 KB

code block:

n;
txt="PV op L";
arr=n%3>0?Math.Floor(n/3):n/3;
Sequence=DSCore.List.Cycle(1..3,arr);
Sup=n-arr*3;
ajout=Sup<=0?null:1..Sup;
serie=DSCore.List.AddItemToEnd(ajout,Sequence);
numb=DSCore.List.Clean(DSCore.List.Flatten(serie));
n<=0?"No List":txt+numb;

Cordially
christian.stan

2 Likes