PYTHON - order a list based in another list

[Ewan_Opie]

To sort by Z then X then Y use the following:

import clr
orglst = IN[0]
orglst.sort(key = lambda orglst: (orglst.Z, orglst.X, orglst.Y))
OUT = orglst

Adaption of the code by:

List sort by key by z then by y then by x location

You could try something like this: [image] import clr orglst = IN[0] orglst.sort(key = lambda orglst: (orglst.X, orglst.Y, orglst.Z)) OUT = orglst