Python Move Curve - Line

Revit
1

I am trying to create a floor using Python.
I want the floor in a different location.

Can someone help me with how to move the Lines?

I found this:

when I try this I get error
*Warning: IronPythonEvaluator.EvaluateIronPythonScript operation failed. *
Traceback (most recent call last):
File “”, line 51, in
AttributeError: ‘Line’ object has no attribute ‘CreateTranslation’

import clr

# import RevitNodes
clr.AddReference("RevitNodes")
import Revit
clr.ImportExtensions(Revit.Elements)

# import Revit Services 
clr.AddReference("RevitServices")
import RevitServices
from RevitServices.Persistence import DocumentManager
from RevitServices.Transactions import TransactionManager

clr.AddReference("RevitAPI")
import Autodesk
from Autodesk.Revit.DB import *

# import system.
import System
from System.Collections.Generic import *
# get the current Revit document. 
doc = DocumentManager.Instance.CurrentDBDocument

floors = FilteredElementCollector(doc).OfCategory(BuiltInCategory.OST_Floors).WhereElementIsElementType().ToElements()
levels = FilteredElementCollector(doc).OfCategory(BuiltInCategory.OST_Levels).WhereElementIsNotElementType().ToElements()

def createCurve():
	l = 200
	h = 200
	p_1 = XYZ(0, 0, 0)
	p_2 = XYZ(0, h, 0)
	p_3 = XYZ(l, h, 0)
	p_4 = XYZ(l, 0, 0)
	line_1 = Line.CreateBound(p_1, p_2)
	line_2 = Line.CreateBound(p_2, p_3)
	line_3 = Line.CreateBound(p_3, p_4)
	line_4 = Line.CreateBound(p_4, p_1)
	curveArray = CurveArray()
	curveArray.Append(line_1)
	curveArray.Append(line_2)
	curveArray.Append(line_3)
	curveArray.Append(line_4)
	return curveArray
	

myVector =  XYZ(40,50,0);

crvs=createCurve()
for crv in crvs:
	crv.CreateTranslation(myVector);

TransactionManager.Instance.EnsureInTransaction(doc)

floorNew = doc.Create.NewFloor(crvs, floors[0], levels[0], Structure.StructuralType.Footing)

TransactionManager.Instance.TransactionTaskDone()


OUT = floorNew
2

Hi @Justin_Wright,

I could be wrong, but I think it might be a simpler proces to move the actual floor after you have created it, rather then the lines. You can use the ElementTranformUtils Class for this:

image
image1748×929 123 KB

Python:

import clr

# import RevitNodes
clr.AddReference("RevitNodes")
import Revit
clr.ImportExtensions(Revit.Elements)

# import Revit Services 
clr.AddReference("RevitServices")
import RevitServices
from RevitServices.Persistence import DocumentManager
from RevitServices.Transactions import TransactionManager

clr.AddReference("RevitAPI")
import Autodesk
from Autodesk.Revit.DB import *

# import system.
import System
from System.Collections.Generic import *
# get the current Revit document. 
doc = DocumentManager.Instance.CurrentDBDocument

floors = FilteredElementCollector(doc).OfCategory(BuiltInCategory.OST_Floors).WhereElementIsElementType().ToElements()
levels = FilteredElementCollector(doc).OfCategory(BuiltInCategory.OST_Levels).WhereElementIsNotElementType().ToElements()

def createCurve():
	l = 200
	h = 200
	p_1 = XYZ(0, 0, 0)
	p_2 = XYZ(0, h, 0)
	p_3 = XYZ(l, h, 0)
	p_4 = XYZ(l, 0, 0)
	line_1 = Line.CreateBound(p_1, p_2)
	line_2 = Line.CreateBound(p_2, p_3)
	line_3 = Line.CreateBound(p_3, p_4)
	line_4 = Line.CreateBound(p_4, p_1)
	curveArray = CurveArray()
	curveArray.Append(line_1)
	curveArray.Append(line_2)
	curveArray.Append(line_3)
	curveArray.Append(line_4)
	return curveArray
	
myVector =  XYZ(40,50,0);

crvs = createCurve()

TransactionManager.Instance.EnsureInTransaction(doc)

floorNew1 = doc.Create.NewFloor(crvs, floors[0], levels[0], Structure.StructuralType.Footing)

floorNewTranslated = ElementTransformUtils.MoveElement(doc, doc.Create.NewFloor(crvs, floors[0], levels[0], Structure.StructuralType.Footing).Id, myVector)

TransactionManager.Instance.TransactionTaskDone()

OUT = floorNew1, floorNewTranslated

Link to the method used.

Mind that you need to to use MoveElements if you’re moving more than one element.

1 Like