Extract numbers of srings list which are in between brackets and leave a prefix and the number as result. For example:
original list=[[“cat/badboy [3421]”],[“cat/goodboy [5634]”]],[[“cat/badboy [3421]”],[“cat/goodboy [5634]”]]
result desired=[[“cat/3421”],[“cat/5634”]],[[“cat/3421”],[“cat/5634”]]
Basically I would do this: remove any string between “/” and “[” and remove also “]”.
with nodes I wuld do it with string.split with separators as “/”,"[","]" and remove from the 3 results, the one in the middle and concatenate in a single string those remaining results.
or I would extract only the number between brackets and add the same prefix “cat/” in front of the number extracted.
I got this python code to extract numbers from string but I do not know how to add the condition to take the number between brackets:
import clr
# True if character is a number, false otherwise
def IsNum(char):
try:
int(char)
return True
except ValueError:
return False
# Join a single list of characters into a string
def JoinChars(chars):
if not chars:
return None
elif len(chars) == 1:
return chars[0]
else:
return "".join(chars)
# Return a list of contiguous numbers from a string
def StringToNumbers(str):
# Extract lists of contiguous number characters
nums = []
lastWasNum = False
ls = []
for i in range(len(str)):
if IsNum(str[i]):
ls.append(str[i])
lastWasNum = True
elif str[i] == "." and lastWasNum:
ls.append(str[i])
elif lastWasNum:
nums.append(ls)
ls = []
lastWasNum = False
if i == len(str)-1 and ls:
nums.append(ls)
# Cast character strings to numbers
if not nums:
return [None,None]
elif len(nums) == 1:
asStr = JoinChars(nums[0])
return [asStr,float(asStr)]
else:
asStr = []
asNum = []
for i in range(len(nums)):
oneStr = JoinChars(nums[i])
asStr.append(oneStr)
asNum.append(float(oneStr))
return [asStr,asNum]
str = IN[0]
OUT = StringToNumbers(str)
Regular expressions will be your friend here, and in fact may be the best path forward for many of the string questions you are running into. Worth taking the time to study up on them.
This might work, but I haven’t tested.
Import re
baseString = IN[0]
numbersInBrackets = re.findall(‘[\d]’, baseString)
def find_between( s, first, last ):
try:
start = s.index( first ) + len( first )
end = s.index( last, start )
return s[start:end]
except ValueError:
return “”
out =
for lst in original_list:
for i in lst:
for s in i:
xx = find_between (s, “[” , “]”)
yy = find_between (s, “” , “/”)
zz = [xx + “/” + yy]
out.append(zz)
Retyping this from another source, but this should do the trick if formatting is right:
import re
strings = IN[0]
results = []
for str in strings:
found = re.findall(“(\w+)/|\[\d+\]”, str)
results.append([f for set in found for f in set if f != “”])
OUT = results
once the groups are established, I use the re.sub() method to replace the full match by the concatenation of the 2 groups with '\g<1>\g<2>' to access them
The solution of @c.poupin gave me same identical result that the string input so maybe it does not work with sublists or did not have the function to find a number between brackets.
The solution of @Alien makes Dynamo not responding like crashing for many minutes and the result looks like millions of single item sublists with the value “/”, so I do not know what can be wrong.
def find_between(s,first,last):
try:
start = s.index(first) + len(first)
end = s.index(last,start)
return s[start:end]
except ValueError:
return ""
cropedlist = []
for lst in parentjoinedlist:
for i in lst:
for s in i:
xx = find_between(s,"[","]")
yy = find_between(s,"","/")
zz = [xx+"/"+yy]
cropedlist.append(zz)
OUT = cropedlist
something to mention and perhaps the issue is that the input list contains sublists in which not all items have numbers between brackets and “/” separator with string in between
I am doing like the sample with sublists with list of items, but the items with brackets [ ] are in a variable index, so there are many other items, without brackets contained in the string. All items of any sublist are strings.
hello it gives me result, although the result now is sublists of one item and all the strings are modified or removed, majority are replaced by “/”, and the items which had number between brackets looking like number first plus “/” plus the prefix. I think this needs condition that if string does not contain number between brackets that do not edit the item leave as it is.
@c.poupin it works but it can modify other string with separator as space or “-”, so very dangerous @Alien it does something not wanted
the solution of @c.poupin apparently works in that simple example but in my real case it modifies of other string item values not expected.
the solution of @Alien looks interesting with split method but for some reason it is getting wrong items of sublists given, maybe it needs to work with sublists.
the solution of @jacob.small looks interesting but I do not understand the warnings at all, new for me.
Nothing works yet, perhaps changing the sample exercise or the question would be easier. I am thinking only extract the number between brackets replacing the original string and leave the rest of string that do not contain a number between brackets
Can you copy EXACTLY what you’re feeding into the nodes please?
I fed in exactly what you wrote in your first example:
original list=[[“cat/badboy [3421 ]”],[“cat/goodboy [5634 ]”]],[[“cat/badboy [3421 ]”],[“cat/goodboy [5634 ]”]]
If you’re mixing up the lists with things on different levels of nesting then my code needs a tweak as it’s only looking at one level.
