I’m a beginner in dynamo, how do I write:
{(u,v) | 0 <= u >= 2*PI , 0 <= v >= PI}
X = cos(u)
Y = sin (u)
Z = v
So that I can draw this cylinder’s geometry? Using codeblock or python script?
Thank you
I’m a beginner in dynamo, how do I write:
{(u,v) | 0 <= u >= 2*PI , 0 <= v >= PI}
X = cos(u)
Y = sin (u)
Z = v
So that I can draw this cylinder’s geometry? Using codeblock or python script?
Thank you
Thank you.
The first question is how come if I write it in codeblock it doesn’t work?
Second I would like to draw it with a curve, the shape is a cylindrical spiral.
I’d like to apply the code template to other shapes, like in the circular shape.