Loop/Imperative not working

Developers
,
1

Hi All,
I’m trying to find a loop for dyfining how many views i can place in a length on a sheet. Only all the views have different widths.

When the length on my sheet is to small for the next view, I would like to place the next view is a new row(sublist). Can somebody help me out?

image
image.jpg1490×1426 502 KB

2

It does exactly what you’re telling it to do i.e. it checks if the space left after the view is > 0. But that space might still not be enough to place a view there. That’s why you’re getting the negative value on the next round:

image
image.png1204×828 69.6 KB

That could be a quick fix, but I’m not sure if that’s the best approach for what you’re after.

3 Likes
3

Hi Viktor,

Thanks for the quick reply. It’s an answer for the 1/3 :wink:

Let me try to explain my other questions:

1)The outcomming lists are now created per item from the “width” list (see 571-145-145-145) to 0. Is it also possible to create lists that run through the “width” list, so 0 = <571-145 -205-85-86.

2)It would be great if a new list was made after which “sheet” is reset to the starting value and the items in “width” continue. So the 2nd list = values 571-115-65-115.

Sorry, I’m just starting with Python :S

4

Tried unsuccessfully translating this into design script but this works in Python:

sheet = IN[0]
widths = IN[1]
bodem = IN[2]

output = []
t = []
c = sheet
tot = len(widths)-1
for i, w in enumerate(widths):
	c -= w
	if c >= bodem:
		t.append(c)
	else:
		output.append(t)
		c = sheet - w
		t = [c]
	
	if i == tot:
		output.append(t)

OUT = output

viewonsheet2
viewonsheet2.png692×432 16.9 KB

1 Like
5

Nice suggestion! I have to find out some new commando’s again :wink: thanks!

Your example looks good. Now I tried it with a longer list (old list x2). In list1 the imput (sheet) is exceeded, see image.

image
image.png1316×1360 279 KB

I’ve combined your solution with the solution of Viktor like this, and it worked out!
image

Thanks All!!

the code:
sheet = IN[0]
widths = IN[1]
bodem = IN[2]

output =
t =
c = sheet
for i, w in enumerate(widths):
c -= w
if (c-w) >= bodem:
t.append(w)
else:
output.append(t)
t = [w]
c = sheet

if i == len(widths)-1:
	output.append(t)

OUT = output.

6

Ai…a little bit to soon. Somehow the operation “-=” gives an error.
Please some help again…
image

7

Take a look at this:

8

Thanks for the link, I understand the command but I don’t get the error with this command on list and float. The script works perfect when I enter just a number in a code block en put this in IN[0].

9

image
image.jpg1223×696 153 KB

1 Like
10

Super Victor! I gues I get the point. In the formula we couldn’t use a list on “c=sheet”.
I thought it was tackled at the input on line 7.
In dynamo I used to deconstruct node before IN[0], nice to see how to fix it python.

Thanks again!