If with empty list

Revit
1

Hello,

If my string.length = empty i want to replace it with a list of n items “1”
But if it is not empty i want to use the values from string.length.

But if i put the “Empty list” value to the if node i get the “empty list” as a result.

afbeelding.png1491×739 211 KB

Thanks
Edwin

2

Try the ScopeIf node instead.

1 Like
3

With the ScopeIf the program keeps running in a loop

4

Ugh, yeah, that node sometimes is buggy.
In that case use the workaround I posted here:

5

Still not working as it should be see the dyn file.

at the bottom the flatten list has 3 items so List.IsEmpty is false but the “answer” is empty list.

If - Empty list.dyn (11.5 KB)

6

And … you stumbled across another Dynamo bug. :slight_smile:
Don’t use the same variable name in both code blocks.
Try “seq1” and “seq2” instead…

7

Thank you very much for your replies and time it works just fine.

Edwin

9

Thank you Erfajo,

But i do not want to replace the “Empty List”, what i want is when there is an “Empty List” (always 1 item) replace it with a list with n items with value 1.

Edwin.

11

Your list.replace should do the trick too.

1 item empty list comes out a boolmask node if the condition does not excist from there its an empty list.

afbeelding.png1123×428 117 KB

thnkx

Edwin

12

I think this is similar to what I tackled last week, I ended up using the “replace by condition node”. Another option for anyone who’s interested:

This shows the result when the list isn’t empty:

This shows the result when the list is empty:

image.png1409×431 51.2 KB

Hope this helps,

TJ

1 Like