How to create an attractor point within a decreasing sine curve amplitude?

[joavegaco]

Hello to everyone

I want to know if there’s a way to create a sine curve like this, but like a gaussian bell.

How to create a decreasing sine curve amplitude?

You could also do it mathematically (Should also be possible with nodes) [sine_2020-12-02_08-26-56] n = 500; w = 10; h = 4; x = 0..Math.PI*2*10..#n; y = Math.Sin(0..360*w..#n) * (h..0.1..#n); p = Point.ByCoordinates(x,y); c = NurbsCurve.ByPoints(p); To make it flow along a base curve, a little more work [sine_2020-12-02_08-29-50] //Base Curve c1 = NurbsCurve.ByPoints (Point.ByCoordinates([0,10,50],[0,10,0])); //Number of Divisions n = 500; //Scale Wave Extent w = 10; //Scale Wave Height …

Can I move the maximum peak with an attractor point?

Lots of thanks

[Vikram_Subbaiah]

@joavegaco

Can I move the maximum peak with an attractor point?

This should get you close

sineCurve.dyn (12.4 KB)

//Number of Points
ct = 200;

//Amplitude Scale
as = 2;

//Period Scale
ps = 8;

//Base Curve
bc = NurbsCurve.ByControlPoints(Point.ByCoordinates([0,10,40,50],[0,20,20,0]));
cp = bc.PointAtParameter(0..1..#ct);
cn = bc.NormalAtParameter(0..1..#ct);

//Sine Curve
ds = Math.Sin(0..360*ps..#ct)*2;
ic = Math.RemapRange(at.DistanceTo(cp),as,0);
nc = NurbsCurve.ByPoints(cp.Translate(cn,ds*Math.Pow(ic,2)));

[joavegaco]

Thanks a lot. Dynamo is cool.