Hello, I want to change the value of the sublist item to an empty list based on the index. I just only want to change {0,0}, {1,1}, {2,2} surface to empty list Is it possible like to be picture?? [11] [22]

list.dyn (10.5 KB) [image] This is the script attached in the message. @AmolShah , How you have increase the length of Watch node?

Hello @whup Hope this will solve your problem [image] list.dyn (6.3 KB)

THANK YOU FOR YOUR REPLY The result is not returned, it returned NULL. [55]

oh sorry i forgot to run it worked!

I’m really sorry but how can I express the index of a sublist like {0,0}, {1,1}, {2,2}… [41]

No need to create Sub index, for example you need to delete {0,0},{1,0}{2,0} then directly create the list of [0,1,2]

It seems to have been misdirected. i want to delete {0,0}, {1,1},{2,2},{3,3}…

So in this case, Number of item in main list and number of item in each sublist remain same ?

list.dyn (6.9 KB) Try with this one [image]

How can I remove sublist value by index

AmolShah September 28, 2021, 6:38am 18

@honeyjain619 It’s because I’m using Core 2.11.x via Sandbox

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