Get graph filename?

Developers
1

Hi all,

I am wondering if there is a way to programmatically get the active Dynamo graph’s filename? I did some research but came up empty:

  • Example by Mark Thorley (But I cannot find any reference to Dynamo.Applications.DynamoRevit.RevitDynamoModel; ) link

  • Tried accessing it through the viewmodel - no luck either

  • Searched through the Dynamo repo for examples with keywords like ‘workspace’ and ‘filename’

  • On this forum here

I think what I have to do is to get the current Dynamo graphs’ workspace but I don’t know how to do it. I could then get the filename with through Dynamo.Graph.Workspaces.WorkspaceModel

Thanks for the help!

2

This should help you get the FileName of the currently opened Dynamo Graph, though note it only works for Dynamo when it is hosted within Revit.

2 Likes
3

Thanks Brendan, I’ve seen this before:

# access to the current Dynamo instance and workspace
dynamoRevit = Dynamo.Applications.DynamoRevit()
currentWorkspace = dynamoRevit.RevitDynamoModel.CurrentWorkspace

Thing is, as you mention, it will only work with Dynamo for Revit and I’m using Core :upside_down_face:

Could there be a similar (simple) solution for Core as well?

Thanks again for your help!

4

@john_pierson did you ever do this for Core too dude? :smiley: Or was it just D4R?

5

Hi @Michael684

Is this what you want?

image
image1920×820 249 KB

8 Likes
6

This is awesome @Kulkul ! :raised_hands:

3 Likes
7

@Kulkul that’s great! Thank you so much!!

For those wondering, here is the same solution in C#:

string graphPath = Dynamo.Events.ExecutionEvents.ActiveSession.CurrentWorkspacePath;
string graphName = graphPath.Substring(graphPath.LastIndexOf('\\') + 1, graphPath.Length - graphPath.LastIndexOf('\\') - 1);
1 Like
8

You’re Welcome!

1 Like
9

I have added @Kulkul version onto the link below and added a way to just get the file name with and without the file type.

2 Likes
10

Hello @Kulkul,

thanks for this amazing solution. I tried to use your code in a user-defined-node but it does not get the path. Is it possible to make it run inside a node?

Thank you very much!

11

Could you share user defined node?

1 Like
12

Thank you very much for your help @Kulkul.

I tried some stuff and saw that I have to user Passthrough after node to another Python node. Now it works.
Awesome work!

13

I’m trying to create a node based off your code.
It works the first time I run it, but a second Run in the same Dynamo session returns nul.
Exact same code, not changing anything. All I’m doing is running it a second time

import clr
clr.AddReference('DynamoServices')
from Dynamo.Events import *

OUT = ExecutionEvents.ActiveSession.CurrentWorkspacePath