I have a series of lines (shown)
and the intersection points (also shown)
All the lines are in 1 list and all the points are in another list.
How do I work out area of the enclosed areas without explicitly telling the computer which points + lines enclose A and which lines and points enclose B.
Suggestions please 
Hi @Alien is it something here you are after it will give you 2 closed loop
What package is the curves shatter from?
this one is from ampersand and polycurve is the same…polycurve simplify is from sparrow all written in designscript/python
Thanks, I’ll have a look
yeps try it 
Hi Christian is that separationline then, dont think we can use detail and modelline as separation, i cant …
but we can just create the separation and create the room as well if we want in same run
This was the route I would have gone, though entirely Python based as I wouldn’t want anything other than my geometry in the memory. My map was:
m
Did I mention those are lines in Dynamo… And the points are just the intersections (I made another post about this one because my code wasn’t removing the lines (it does now)).
I was hoping for a mathematical solution rather than a , “translate to Revit, create stuff” solution (hence the original post name 
).
This is my list of curves:
Curve(StartPoint = Point(X = -8171.266, Y = 2648.234, Z = 4000.000), EndPoint = Point(X = 603.734, Y = 2648.234, Z = 4000.000))
Curve(StartPoint = Point(X = -7371.266, Y = -4901.766, Z = 4000.000), EndPoint = Point(X = -7371.266, Y = 3098.234, Z = 4000.000))
Curve(StartPoint = Point(X = 4478.734, Y = -4101.766, Z = 4000.000), EndPoint = Point(X = -7821.266, Y = -4101.766, Z = 4000.000))
Curve(StartPoint = Point(X = 3678.734, Y = 5698.234, Z = 4000.000), EndPoint = Point(X = 3678.734, Y = -4551.766, Z = 4000.000))
Curve(StartPoint = Point(X = 878.734, Y = 3448.234, Z = 4000.000), EndPoint = Point(X = 878.734, Y = -4551.766, Z = 4000.000))
Curve(StartPoint = Point(X = -546.266, Y = 1848.234, Z = 4000.000), EndPoint = Point(X = -546.266, Y = 6048.234, Z = 4000.000))
Curve(StartPoint = Point(X = -996.266, Y = 5248.234, Z = 4000.000), EndPoint = Point(X = 4478.734, Y = 5248.234, Z = 4000.000))
Curve(StartPoint = Point(X = -996.266, Y = 2648.234, Z = 4000.000), EndPoint = Point(X = 1328.734, Y = 2648.234, Z = 4000.000))
And it didn’t work at all.
I guess it’s because the curves extend past the intersect point?
Goddag @Alien hmm not sure could you share the rvt you try on…so we can see whats fail ? and keep in mind it want work in some situaton
The curves are Dynamo curves in Dynamo.
It only picks up the rectangle not the ‘L’ shape.
What packages is the polycurve.Simplify from?
This is with these curves:
Curve(StartPoint = Point(X = -7871.266, Y = 2648.234, Z = 4000.000), EndPoint = Point(X = 303.734, Y = 2648.234, Z = 4000.000))
Curve(StartPoint = Point(X = -7371.266, Y = -4601.766, Z = 4000.000), EndPoint = Point(X = -7371.266, Y = 2798.234, Z = 4000.000))
Curve(StartPoint = Point(X = 4178.734, Y = -4101.766, Z = 4000.000), EndPoint = Point(X = -7521.266, Y = -4101.766, Z = 4000.000))
Curve(StartPoint = Point(X = 3678.734, Y = 5398.234, Z = 4000.000), EndPoint = Point(X = 3678.734, Y = -4251.766, Z = 4000.000))
Curve(StartPoint = Point(X = 878.734, Y = 3148.234, Z = 4000.000), EndPoint = Point(X = 878.734, Y = -4251.766, Z = 4000.000))
Curve(StartPoint = Point(X = -546.266, Y = 2148.234, Z = 4000.000), EndPoint = Point(X = -546.266, Y = 5748.234, Z = 4000.000))
Curve(StartPoint = Point(X = -696.266, Y = 5248.234, Z = 4000.000), EndPoint = Point(X = 4178.734, Y = 5248.234, Z = 4000.000))
Curve(StartPoint = Point(X = -696.266, Y = 2648.234, Z = 4000.000), EndPoint = Point(X = 1028.734, Y = 2648.234, Z = 4000.000))
sparrow
Its hard to say…i will need the file for test…
Cells.dyn (33.0 KB)
i mean the rvt with lines
They aren’t Revit lines.
I’ve extracted them from intersections of planes and edges
arhhh I see
