Hello fellow Dynamo programmers, I am quite advanced in using Dynamo and working with geometries, but I am currently facing a problem that is too complex for me to solve on my own. I hope someone here can help me with it. I need to identify all the floor space in a room that meets the 1.8 x 1.8 met…

here’s an alternative idea using a pseudo scan the process obtain room orientation according to the 2 vectors (orientation), perform a scan by ray (Unbound Line Intersection with room limits) group the lines obtained (less than 1.8m) by distance for each group, get the aligned boudingbox and extr…

A L shape is fairly simple I can use the split node for it and then check the individual squares on its 1,8m perimeter lines. but yea I haven’t taken the column into account yet :sweat_smile:

The logic is based on the Dutch building code, which states that any floor area smaller than 1.8 meters cannot be considered usable for long-term stays by people. Therefore, in architectural plans, you need to clearly distinguish between the total floor space and the officially usable floor space (a…

Another approach. Get room outlines, including the columns (black lines in my amazing illustration below). Get points along each line (red dots). I’ve only drawn a few but obviously you could do these much closer, maybe every 100mm. Measure the distance from each point to the nearest object at a …

If I understand your approach correctly, you want to group all the lines below 1.8m. However, if you do that, you will get the blue square and exclude too much area. In addition to your approach, I thought about grouping them by length (red squares), but if you do that, you will miss the yellow area…

I meant into several groups, but you’re right about the yellow… I wonder if you could do corners only… Then the column lines would all be grouped together and you’d get the yellow bit then.

[image] Room - 'remove' area less than X wide Revit I searched but couldn’t find a any topic related to this. Is there a way to create a Curve from a Room minus the area less then X wide [image] Who can point me at the right direction or related topic? Maybe this …

Thank you for pointing that out. I have the same question. I haven’t tried that method of getting the correct floor area yet. Maybe later today I can put it into practice.

You might end up with a combination of all the suggestions :upside_down_face:. Maybe you can also do something with Spaces.

I don’t think anyone’s got a perfect solution for this yet? Be fun to see alternatives. I reckon my idea’s the most fun tho :stuck_out_tongue:

A modified flood fill is the way I would tackle this. Use a 1.8 x 1.8m ‘pixel’ and it would probably have to check for wall angles and rotate the whole algorithm to suit. Scan across from a start corner at 1.8m jumps, once you have a collision bisect back and forth until it aligns with the opposit…

Excluding parts of a surface that don't meet the 1.8m by 1.8m minimum requirements

Revit

bvs1982 September 30, 2024, 5:50pm 17

Maybe this can also be useful.

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Excluding parts of a surface that don't meet the 1.8m by 1.8m minimum requirements

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