TypeCast GeometryElement to Solid using Python

Developers
1

I am trying to get the faces of an element using Python code.

I am following the example from the Revit API docs, on how to get the Faces property of a Solid class object.

link to + excerpt of the example:
[http://www.revitapidocs.com/2019/b45fa881-3077-409c-0ef1-5d42744e7429.htm]

```
 Autodesk.Revit.DB.Options opt = new Options();
    Autodesk.Revit.DB.GeometryElement geomElem = wall.get_Geometry(opt);
    foreach (GeometryObject geomObj in geomElem)
    {
        Solid geomSolid = geomObj as Solid;
        if (null != geomSolid)
        {
            int faces = 0;
            double totalArea = 0;
            foreach (Face geomFace in geomSolid.Faces)
            {
```

my python code:

doc = DocumentManager.Instance.CurrentDBDocument
element = UnwrapElement(IN[0])
options = Autodesk.Revit.DB.Options()

geometryInstance = element.get_Geometry(options)

inst_geom = []

for i in geometryInstance:
	inst_geom.append(i.GetInstanceGeometry()) 

OUT = inst_geom[0]

Up to here, all is well. Dynamo output looks like this:

image

Now if i add a small piece of code:

doc = DocumentManager.Instance.CurrentDBDocument
element = UnwrapElement(IN[0])
options = Autodesk.Revit.DB.Options()

geometryInstance = element.get_Geometry(options)

inst_geom = []

for i in geometryInstance:
	inst_geom.append(i.GetInstanceGeometry())

faces = []

for i in inst_geom:
	faces.append(i.Faces)

OUT = faces[0]

I get this:

image

So… to me this looks like Python is failing to read the Autodesk.Revit.DB.Solid as a Solid, instead it is reading it as a GeometryElement. So I would need to typecast this somehow. As the example says:

Solid geomSolid = geomObj as Solid;

How can I do this in Python?

2

My bad. I was in the wrong hierarchy. Solution is:

for i in inst_geom[0]:
	faces.append(i.Faces)

image

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