Hello,
I got for example this list [abracadabra,cabra,malacabra,caca] and I want to remove the part of the strings that are ending in this string text “bra”, so I would get a result like this in the string list: [abracada,ca,malaca,caca]
The most similar OOTB node is String.TrimTrailingWhitespace, but instead of space I need specific string to remove.
There are a number of ways to go about this. There is a python method called rstrip() that does exactly what you’re looking for. Or you could get a little creative with some node logic; Example: Split the strings at their last three characters, check to see if those chars == "bra" and return either the original or split string depending on that result.
so it would be something like that?:
newlist=list.rstrip(“bra”)
I get this warning for a list AttributeError: ‘list’ object has no attribute ‘rstrip’
You would use the method on the string, so you have to loop through each string in the list, but yes.
Need to tell python that it needs to loop over the objects in the list via a for loop or list comprehension.
Alternatively you can wrap the python in a custom node to allow dynamo to handle the looping for you.
You can try this:
lst = ['abracadabra','cabra','malacabra','caca']
OUT = [i[:-3] if i.endswith('bra') else i for i in lst]
it works if I remember to change the number of characters to remove from the end based on the string to remove hehe, I can live with it, thanks
To avoid that, use the len function:
lst = ['abracadabra','cabra','malacabra','caca']
to_remove = 'bra'
OUT = [i[:-len(to_remove)] if i.endswith(to_remove) else i for i in lst]
OUT = [ i.rstrip(“bra”) for i in IN[0] ]