Hello,
Learning…
Why does my function not work when the imput comes from IN[0] ? how can i convert my Input not beeing a list or viceversa, how can i change my code that is dealing with a list-imput, i need a loop at some place? inside the function or outside?
def concat(*args, sep="."):
return sep.join(args)
x = concat(IN[0])
OUT = x
it is working:
def concat(*args, sep="."):
return sep.join(args)
x = concat("earth", "mars", "venus")
OUT = x
How can i deal with the issue , whether i don`t know if it is a list or a single value ?
KR
Andreas
Hi,
This works for me, I’m not sure what the * notation did, (I’m not that good at Python)…
You’ll see ‘isinstance’ in lots of nodes to ensure things are always in a list…
Hope that helps,
Mark
@Mark.Ackerley
they call it KeyParameters … *
There is a difference between Positional Arguments and Keyword Arguments ( As in my tutorial)
Actually i can`t understand the topic
I guess it is failing because in Dynamo you are passing a List, which has a defined order?
My knowledge is now exhausted 
this is correct, the message kind of contains the issue - *args expects multiple arguments - (variardic)
but you are not passing a variable number of strings, you are passing a single list.
try this:
From my understanding *args means that you have x number of arg inputs to your function. Each argument still requires a singleton in this case, but you can provide as many as you like. A list is still not a singleton. It’s similar to the scalable nodes in Dynamo that allow for +/- number of inputs. You can provide any number of inputs but the structure of the input is still dependent on the function.
if necessary, you can unpack your list at argument,
example with 2 list
