Hello,
Learning…
Why does my function not work when the imput comes from IN[0] ? how can i convert my Input not beeing a list or viceversa, how can i change my code that is dealing with a list-imput, i need a loop at some place? inside the function or outside?
def concat(*args, sep="."):
return sep.join(args)
x = concat(IN[0])
OUT = x
it is working:
def concat(*args, sep="."):
return sep.join(args)
x = concat("earth", "mars", "venus")
OUT = x
How can i deal with the issue , whether i don`t know if it is a list or a single value ?
KR
Andreas
Hi,
This works for me, I’m not sure what the * notation did, (I’m not that good at Python)…
You’ll see ‘isinstance’ in lots of nodes to ensure things are always in a list…
Hope that helps,
Mark
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@Mark.Ackerley
they call it KeyParameters … *
There is a difference between Positional Arguments and Keyword Arguments ( As in my tutorial)
Actually i can`t understand the topic
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I guess it is failing because in Dynamo you are passing a List, which has a defined order?
My knowledge is now exhausted 
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this is correct, the message kind of contains the issue - *args expects multiple arguments - (variardic)
but you are not passing a variable number of strings, you are passing a single list.
try this:
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From my understanding *args means that you have x number of arg inputs to your function. Each argument still requires a singleton in this case, but you can provide as many as you like. A list is still not a singleton. It’s similar to the scalable nodes in Dynamo that allow for +/- number of inputs. You can provide any number of inputs but the structure of the input is still dependent on the function.
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if necessary, you can unpack your list at argument,
example with 2 list
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