List and item

Revit
1

Hello; I want someone to help me, please
In a dynamo, I found a problem, I have 2 lists; One has got 50 items and 52 items respectively or some it alternates so I have to choose always 52 items. How I have to do?

2

Lacing > Longest?

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3

but…when I choose like that, in List.LaceLongest is “null” look like this picture How?.

Screenshot%20(2)
Screenshot (2).png1920×1080 250 KB

4

try this
the first list is a list of lists.
Flatten it first or choose list@level 2
second you’ll need to provide a combinator like ==

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5

please, some example ^^

6

i cant help you with an example
i don’t have Dynamo on this computer.
sorry

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7

your welcome, thank you so much

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8

i want to invite some other guys to help you out

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9

ok. Thak you so much

10

I don’t have your data set, so I cannot confirm, but I think that the reason you have 50 items in the first list is that empty lists don’t count as items.

When you replace the empty lists with an item (in your case a 0), you now have something which is counted, ergo you wind up with a larger count.

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11

When I replace the empty lists with number other than 0, all is the list are still ‘null’.

12

What lists are you referring to? I’m a bit lost here, perhaps the original question wasn’t clear.

Can you post the dyn and any other required files (Revit, excel, etc) to run it, and a an image showing the preview of what you have and markups showing what you want.

Thanks.

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