If statement wrong output

Revit
1

Hello,

I have a problem with 2 lists.
List A has 4 items en list B has 6.
If “true” I expect to get list A and if “false” list B. Somehow in both it return list A.

Does anybody have a clue ?

Best regards, Fred

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2

The If node always returns the same length, using the shortest list’s length. So in this case, when it is false, it returns only the first 4 items of the false list.

Try using ScopeIf, it will return the entire false list.

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3

ScopeIf is a little more complicated than that.
This question has been asked and answered dozens of times already. Please search the forum before asking for help.

4

Thanks Kenny, but with ScopeIf it crashes.

My appologies Nick, but I thought I couldn’t find anything similar.
Just now I found out that it didn’t give list A for both results, but list A for “true” and the first 4 items of list B for “false”.
Because of the identical display of references I could not see the difference. I solved it by using [transpose] and [remove nulls].

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5

That’s actually a clever solution but you should look into the list/index solution for getting the correct output. I’m guessing transpose won’t work as well if you have a more complex list structure.

6

This is my personal favorite method for dealing with this type of issue:

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rslt = [lstA, lstB][test ? 0 : 1];

7

Thanks Jacob,
Works like a charm.
Fred