Hello, in short I am trying to keep a list in tact, but replace all duplicate values, besides the first duplicate, with a string like “X” or something similar. For example, I am trying to take a list like this: “1, 2, 3, 3, 4, 5, 6, 7, 7, 7, 8, 9, 10” Into a single list like this: “1, 2, 3, X, 4…

I would use Python for this. You could make an empty list, pass it through and if statement to check if each value is in the new list, then if not append it and if so append X instead. I’m on my mobile but it’s be like this… oldlist = IN[0] newlist = for i in oldlist: if i in newlist: newlist…

Hi @markb43 , welcome to the Dynamo community! As @GavinNicholls mentioned, I would go with python in this one. But here’s 2 more possible solutions that you can implement: [1] Or [2] lst; replace = "X"; [Imperative] { for(i in GetKeys(lst)) { count = List.Count(lst[i]); if (count>1) …

Hi @markb43 , Welcome to the Dynamo community. You can do something like this as well: [image] Please help python replace text Revit @toantrungthach Here you go: [image] OUT = [IN[0][0]] OUT.extend("OK" if IN[0][x] == IN[0][x-1] else IN[0][x] for x in range(1,len(IN[0]…

You could refer to the code below and do this with nodes too (if you prefer) [replace] idx = 0..List.Count(lst)-1; unq = List.IndexOf(lst,List.UniqueItems(lst)); dup = List.SetDifference(idx,unq); rpl = List.Contains(dup,idx<1>) ? "X" : lst; EDIT: Line 3 is actually unnecessary. [replace1] Li…

Please help python replace text OUT = [IN[0][0]] OUT.extend(“OK” if IN[0] == IN[0][x-1] else IN[0] for x in range(1,len(IN[0]))) This one works great, Thanks!

Duplicates in Lists

Lists-Logic

markb43 November 8, 2021, 3:11pm 7

This one works great, Thanks!

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