I’d like to get the outermost boundary/a boundary that encloses the polygons but I don’t have any good idea on how to make dynamo to automatically get those points. [P_20170921_112348]

Convex Hull 2D Take every odd or even curve of the resulting polygon Intersect each of those curves with the next one Create new polygon from resulting points This will give you both possible solutions for polygon E

Come to think of it you can get the desired result right away if in step 2 you filter out all curves that coincide with any of the boundary curves of A, B, C and D: Convex Hull 2D Filter out all curves from the resulting polygon that coincide with any of the boundary curves of A, B, C and D Inters…

Great solution as always @Andreas_Dieckmann !

You could also extend this with the Rotating Calipers algorithm and find the minimal area rectangle that encompasses all of the shapes.

[image] Get an outer boundary of multiple polygons (Room Boundaries) Geometry As Andreas confirmed, the convex hull will get rid of all concave parts of the shape, but will be much faster to compute. Not sure if it will be good enough for your needs, because you have yet t…

I kept developing my graph and as I went on I found something rather confusing. When I converted my curves onto polygons and then onto sufraces to thicken them some of the normals were flipped, as you see on the first image. My solution was to decompose the surfaces and filter out the negative and …

You could just use your Z vector for driving the thickness (negative thickness will extrude the other way). No need to filter or create new surfaces.

Solved by connecting Polygon.ByPoints to Curve.ExtrudeAsSolid. The problem only showed whenever I tried to thicken a Surface.ByPatch

Boundary that encloses polygons

Geometry

jair_gh September 22, 2017, 2:03pm 7

@Andreas_Dieckmann
Thank you. I managed with a simple convex hull.
So far works for what I need .

Concave Hull (Alpha Shape) from list of points with Python?

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Boundary that encloses polygons

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