Try statement hands in, does not work?

Developers
1

Hello,

i stuck , i am sure it is a small detail:

numbers = IN[0]
divisor = IN[1]

def divide(x, y):
	try:
		result = x / y
	except ZeroDivisionError:
		return (0.00)
	else:
		return(result)
	finally:
		return(result)
		
result = []



for i in divide(numbers,divisor):
	result.append(i)
	
OUT = result

2022-05-30_09h38_18
2022-05-30_09h38_181183×315 22.8 KB

How can i handle errors?

KR

Andreas

2

Have you tried declaring local variable result before assigning something?

numbers = IN[0]
divisor = IN[1]

def divide(x, y):
    result = 0
	try:
		result = x / y
	except ZeroDivisionError:
		return (0.00)
	else:
		return(result)
	finally:
		return(result)
		
result = []



for i in divide(numbers,divisor):
	result.append(i)
	
OUT = result
3 Likes
3 
numbers = IN[0]
divisor = IN[1]
result = []	


def divide(x, y):	
	try:
		global result
		result = x / y		
	except ZeroDivisionError:
		return (0.00)
	else:
		return(result)
	finally:
		return(result)
		
final = []


for i in divide(numbers,divisor):
	final.append(i)
	
OUT = final

@dylim ,

how do i divine that?

4

i also noticed your two input are list. So you may need to add a loop.

divideResult = [divide(num, div) for num, div in zip(numbers, divisor)]
for i in divideResult :
    final.append(i)
OUT  = final

or

final = [divide(num, div) for num, div in zip(numbers, divisor)]
OUT = final
2 Likes
5

@dylim ,

zip! that was it! but there is still one detail, it gives a emty least insteat of 0.00

	except ZeroDivisionError:
		return (0.00)
6 
	except ZeroDivisionError:
        result = 0
		return result

Can you try this way?

2 Likes
7

@dylim

2022-05-30_10h35_18
2022-05-30_10h35_18510×508 19.3 KB

0.00 is better to remain double. when i use 0 it is a integer
2022-05-30_10h36_19

8

hmm… i think i can do it better but doable option is using float().

except ZeroDivisionError:
result = 0
return float(result)

or

except ZeroDivisionError:
result = 0.00
return result

I don’t know whether it is going to work or not cus i am away from my PC but try and let me know.

2 Likes
9

float is not working with 0… …0.00 works! @dylim

1 Like
10

image
image1066×411 88.1 KB

That’s how I’d do it.
Notice they’re all doubles even if they’re not showing the decimal point.

1 Like
11

The super class of ZeroDivisionError is ArithmeticError. This exception raised when the second argument of a division or modulo operation is zero. In Mathematics, when a number is divided by a zero, the result is an infinite number. It is impossible to write an Infinite number physically. Python interpreter throws “ZeroDivisionError: division by zero” error if the result is infinite number. While implementing any program logic and there is division operation make sure always handle ArithmeticError or ZeroDivisionError so that program will not terminate.

try:
    z = x / y
except ZeroDivisionError:
    z = 0

Or check before you do the division:

if y == 0:
    z = 0
else:
    z = x / y

The latter can be reduced to:

z = 0 if y == 0 else (x / y)

1 Like