So everything that’s not in the asked for list should be moved to the bottom of the list?
yes
So you want to have the rest sorted in order as well?
Guess I’ll have to be combining my two previous not-working solutions…
yes
i my graph i have it working for the a great part but with the words “stoel” and “stoelpoot” it puts the word “stoelpoot” not at the disired location
If you want to do both those things you’re in the same boat as I am now:
Almost
but now i have more items in the new list (19 in the original list and 23 in the new one) and in youre example one les.
And stil the strings wich contains “stoelpoot” become before “stoeltest” and that is not what i want.
I need the strings containing “stoelpoot” after strings that contains only “stoel” .
I know it can be done with a lot of times list.filterByBoolMask after eachother. But both list can change in length and than i have too change the graphs each time.
You don’t need multiple BoolMask nodes, you just need to use the proper list levels. The problem is that stoel
is also going to return stoelpoot
strings and stad
is also going to return stad01
strings. It’s not a huge issue for stoel
because you have stoel
and stoelpoot
in alphabetical order so you could probably just filter by stoel
. But this is an issue when you have stad01
coming before stad
.
This should do it. This keeps the order intact regardless of sorting because it only takes the first match. (The warning is for unmatched elements.)
List.List.Sortby.Numbering op basis van een andere list.dyn (49.5 KB)
i did exactly the same as you did i get warning length list is not equal as length key
i tried it in revit 2018.3 and 2019
The list level should be set for the str
input on String.Contains, not searchFor
. You’re checking each individual string against all the searches. This way you can get the first match if there are more than one.
you are a genius
but it is the same result as my attempt
problem is stoelpoot and stoel
i like it that it is now grouped
Sorry, I forgot to remove that from my list. You would get rid of stoelpoot and only search for stoel. Since the list requires stoel to come before stoelpoot (which sorting will do) you don’t actually need both of them.
Edit: Actually it doesn’t even matter in this case, because it pulls the first match only, so there are no duplicates. It just doesn’t group stoelpoot separately.